A particle is moving with a velocity v^{-} = K (yi^{\^}+xj^{\^}) , where K is a constant. Thegeneral equation for its path is: [9-Jan-2019 Shift 1]

Correct Answer is : y2 = x2 + constant

JEE Main 9 Jan 2019 Shift 1 Solved Paper

Section: Physics

Question : 26 of 90

Marks: +1, -0

A particle is moving with a velocity

−

= K (y

) , where K is a constant. Thegeneral equation for its path is:

[9-Jan-2019 Shift 1]

Go to Question:

Prev Question

Next Question