In the following reaction sequence : \text{I}↙(C_3H_6Cl_2)\stackrel{KOH(aq)}{––––––––>}\text{II}\stackrel{(i) CH_3MgBr}{––––––––––––––>}_{(ii) H_2O\text{/}H^{+}}\text{III}\stackrel{\text{Anhy}{–––––––––––––––––>}.ZnCl_2+\text{Con}.HCl}\text{gives turbidity immediately} The compound \text{I} is : [Main 9 April 2017]

Correct Answer is : CH3−Cl|C|Cl−CH3

C_{|↙{Cl}}H_2-C_{|↙{Cl}}H-CH_3

C_{|↙{Cl}}H_2-CH_2-C_{|↙{Cl}}H_2

CH_3-C^{|↖{Cl}}_{|↙{Cl}}-CH_3

JEE Main 9 April 2017 Paper Solved Paper

Section: Chemistry

Question : 59 of 90

Marks: +1, -0

In the following reaction sequence :

(C3H6Cl2)

KOH(aq)

––––––––>

(i)‌CH3MgBr

––––––––––––––>

(ii)‌H2O/H+

III

Anhy.ZnCl2+Con.HCl

–––––––––––––––––>

gives turbidity immediately

The compound I is :

[Main 9 April 2017]

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