To find the standard potential of M^{3+}\text{/}M electrode,the following cell is constituted : Pt\text{/}M\text{/}M^{3+}(0.001molL^{-1})\text{/}Ag^{+}(0.01molL^{-1})\text{/}Ag The emf of the cell is found to be 0.421 volt at 298 K. The standard potential of half reaction M^{3+}+3e^{−}\to M at 298 K will be : (Given E^{⊖}_{Ag^{+}\text{/}Ag} at 298K=0.80 Volt) [Main 9 April 2017]

JEE Main 9 April 2017 Paper Solved Paper

Section: Chemistry

Question : 36 of 90

Marks: +1, -0

To find the standard potential of M3+/M electrode,the following cell is constituted :

Pt/M/M3+(0.001molL−1)/Ag+(0.01molL−1)/Ag

The emf of the cell is found to be 0.421 volt at 298 K. The standard potential of half reaction M3++3e−→M at 298 K will be :
(Given EAg+/Ag⊖ at 298K=0.80 Volt)

[Main 9 April 2017]

0.38 Volt
0.32 Volt
1.28 Volt
0.66 Volt

Validate

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