The magnetic field in a plane electromagnetic wave is B_y= (3.5 \times 10^{-7}) \sin (1.5 \times 10^3 x+0.5. \times 10^{11} {\t}) {\T}. The corresponding electric field will be [9 Apr 2024 Shift 2]

Correct Answer is : Ez=105sin(1.5×103x+0.5×1011t)Vm−1

{\E}_{ {\y}}=1.17 \sin (1.5 \times 10^3 {\x}+0.5 \times 10^{11} {\t}) {\Vm}^{-1}

{\E}_{ {\z}}=105 \sin (1.5 \times 10^3 {\x}+0.5 \times 10^{11} {\t}) {\Vm}^{-1}

{\E}_{ {\z}}=1.17 \sin (1.5 \times 10^3 {\x}+0.5 \times 10^{11} {\t}) {\Vm}^{-1}

{\E}_{ {\y}}=10.5 \sin (1.5 \times 10^3 {\x}+0.5 \times 10^{11} {\t}) {\Vm}^{-1}

JEE Main 9 Apr 2024 Shift 2 Solved Paper

Section: Physics

Question : 35 of 90

Marks: +1, -0

The magnetic field in a plane electromagnetic wave is By=(3.5×10−7)sin‌(1.5×103x+0.5. ×1011t)‌T. The corresponding electric field will be

[9 Apr 2024 Shift 2]

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