JEE Main 9 Apr 2024 Shift 2 Solved Paper
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Question : 3 of 90
Marks:
+1,
-0
Let
√ 1 − ( y ′ ( t ) ) 2 dt =
y ( t ) dt , 0 ≤ x ≤ 3 , y ≥ 0 y ( 0 ) = 0 x = 2 , y + y + 1
[9 Apr 2024 Shift 2]
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