Let \alpha, \beta ; \alpha>\beta, be the roots of the equation x^2-\sqrt{2} x-\sqrt{3}=0. Let P_n=\alpha^n-\beta^n, n \in N. Then (11 \sqrt{3}-10 \sqrt{2}) {\P}_{10}+(11 \sqrt{2}+10) {\P}_{11}-11 {\P}_{12} is equal to : [9 Apr 2024 Shift 2]

JEE Main 9 Apr 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 19 of 90

Marks: +1, -0

Let α,β;α>β, be the roots of the equation x2−√2x−√3=0. Let Pn=αn−βn,n∈N. Then (11√3−10√2)P10+(11√2+10)P11−11P12 is equal to :

[9 Apr 2024 Shift 2]

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