In a conductor, if the number of conduction electrons per unit volume is 8.5 \times10^{28} m ^{-3} and mean free time is 25 fs (femto second), it’s approximate resistivity is: (m_e = 9.1\times10^{-31 }) [9 Apr 2019 Shift 2]

JEE Main 9 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 6 of 90

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In a conductor, if the number of conduction electrons per unit volume is 8.5×1028m−3 and mean free time is 25 fs (femto second), it’s approximate resistivity is: (me=9.1×10−31)

[9 Apr 2019 Shift 2]

10−8Ωm
10−6Ωm
10−5Ωm
10−7Ωm

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