A particle ‘P’ is formed due to a completely inelastic collision of particles ‘x’ and ‘y’ having de-Broglie wavelengths ‘\lambda_ x ’ and ‘\lambda_ y ’ respectively. If x and y were moving in opposite directions, then the de-Broglie wavelength of ‘P’ is: [9 Apr 2019 Shift 2]

Correct Answer is : λxλy |λx−λy |

{\\lambda_{x} \\lambda_{y}}/{ |\\lambda_{x}-\\lambda_{y} |}

{\\lambda_{x} \\lambda_{y}}/{ |\\lambda_{x}+\\lambda_{y} |}

JEE Main 9 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 30 of 90

Marks: +1, -0

A particle ‘P’ is formed due to a completely inelastic collision of particles ‘x’ and ‘y’ having de-Broglie wavelengths ‘λx ’ and ‘λy ’ respectively. If x and y were moving in opposite directions, then the de-Broglie wavelength of ‘P’ is:

[9 Apr 2019 Shift 2]

λx−λy
λxλy
|λx−λy |
λx+λy
λxλy
|λx+λy |

Validate

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