JEE Main 9 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 26 of 90

Marks: +1, -0

The position of a particle as a function of time t, is given by x(t)=at+bt2−ct3 where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be:

[9 Apr 2019 Shift 2]

a+
b2
3c
a+
b2
2c
a+
b2
c
a+
b2
4c

Validate

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