The position vector of a particle changes with time according to the relation \overrightarrow{r}(t)=15 t^{2} \stackrel{\^}{i}+ (4-20 t^{2} ) \stackrel{\^}{j} . What is the magnitude of the acceleration at t = 1? [9 Apr 2019 Shift 2]

JEE Main 9 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 24 of 90

Marks: +1, -0

The position vector of a particle changes with time according to the relation

→

(t)=15t2

+(4−20t2 )

. What is the magnitude of the acceleration at t = 1?

[9 Apr 2019 Shift 2]

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