JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

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Question : 70 of 90

Marks: +1, -0

If the function f defined on (

π

6

,

π

3

) by f(x)={

√2‌cos‌x−1

cot‌x−1

,

x≠

π

4

k,

x=

π

4

is continuous, then k is equal to:

[9 Apr 2019 Shift 1]

2
1
2
1
√2
1

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