JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Chemistry
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Question : 60 of 90
 
Marks: +1, -0
Liquid ‘M’ and liquid ‘N’ form an ideal solution. The vapour pressures of pure liquids ‘M’ and ‘N’ are 450 and 700mmHg, respectively, at the same temperature.
Then correct statement is:
(xM = Mole fraction of ‘M’ is solution;
xN = Mole fraction of ‘N’ in solution ;
yM = Mole fraction of ‘M’ in vapour phase;
yN = Mole fraction of ‘N’ in vapour phase)
[9 Apr 2019 Shift 1]
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