JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 5 of 90

Marks: +1, -0

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be:

[9 Apr 2019 Shift 1]

642.7 nm
889.2 nm
488.9 nm
388.9 nm

Validate

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