The standard Gibbs energy for the given cell reaction in kJ mol^{-1}at 298 K is: Z n(s)+C u^{2+}(a q) \to Z n^{2+}(a q)+C u(s), E^{\0}=2 V at 298 K [9 Apr 2019 Shift 1]

JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Chemistry

Question : 42 of 90

Marks: +1, -0

The standard Gibbs energy for the given cell reaction in kJ mol−1at 298 K is:
Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s), E0=2V at 298 K

[9 Apr 2019 Shift 1]

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