JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 26 of 90

Marks: +1, -0

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ , where θ is the angle by which it has rotated, is given as 2 kθ2. If its moment of inertia is I then the angular accelerationof the disc is:

[9 Apr 2019 Shift 1]

2k
I
θ
k
2I
θ
k
4I
θ
k
I
θ

Validate

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