JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 11 of 90

Marks: +1, -0

A string is clamped at both the ends and it is vibrating in its 4th harmonic. The equation of the stationary wave is Y=0.3‌sin(0.157x)‌cos(200πt) .The length of the string is: (All quantities are in SI units.)

[9 Apr 2019 Shift 1]

40 m
20 m
80 m
60 m

Validate

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