The magnetic field of a plane electromagnetic wave is given by: \overrightarrow{B}=B_{0} \stackrel{\^}{i}[\cos (k z-\\omega t)]+B_{1} \stackrel{\^}{j} \cos (k z+\\omega t) Where B_{0}=3 \times 10^{-5} T and B_{1}=2\times 10^{-6} T The rms value of the force experienced by a stationary charge Q=10^{-4} C at {z}= {0} is [9 Apr 2019 Shift 1]

JEE Main 9 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 1 of 90

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The magnetic field of a plane electromagnetic wave is given by:

→

=B0

[cos(kz−ωt)]+B1

‌cos(kz+ωt) Where B0=3×10−5T and B1=2×10−6T
The rms value of the force experienced by a stationary charge Q=10−4C at z=0 is

[9 Apr 2019 Shift 1]

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