JEE Main 8 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 70 of 75

Marks: +1, -0

The differential equation of the family of curves, x2=4b(y+b), b ∈ R, is

[8 Jan 2020 Shift 2]

x(y’)2=x+2yy’
x(y′)2=2yy′−x
xy"=y′
x(y′)2=x−2yy’

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