JEE Main 8 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

© examsiri.com

Question : 54 of 75

Marks: +1, -0

If I=

2

∫

1

dx

√2x3−9x2+12x+4

, then

[8 Jan 2020 Shift 2]

1
9
<I2<
1
8
1
16
<I2<
1
9
1
6
<I2<
1
2
1
8
<I2<
1
4

Go to Question:

Prev Question

Next Question