JEE Main 8 Jan 2020 Shift 2 Solved Paper

Section: Physics

Question : 1 of 75

Marks: +1, -0

A s shown in figure, when a spherical cavity (centred at O) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be detemined by the equation :

[8 Jan 2020 Shift 2]

(R2−R+1)(2−R)=1
(R2+R−1)(2−R)=1
(R2+R+1)(2−R)=1
(R2−R−1)(2−R)=1

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