The inverse function of f(x)={8^{2x}-8^{-2x}}/{8^{2x}+8^{-2x}},x \in(-1,1), is [8 Jan 2020 Shift 1]

Correct Answer is : 14(log8e)loge(1+x1−x)

1/4(\log_8e)\log_e(\frac{1-x}{1+x})

1/4(\log_8e)\log_e(\frac{1+x}{1-x})

JEE Main 8 Jan 2020 Shift 1 Solved Paper

Section: Mathematics

Question : 67 of 75

Marks: +1, -0

The inverse function of f(x)=

82x−8−2x

82x+8−2x

,x∈(−1,1), is

[8 Jan 2020 Shift 1]

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