JEE Main 8 Jan 2020 Shift 1 Solved Paper

Section: Chemistry
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Question : 49 of 75
 
Marks: +1, -0
What would be the electrode potential for the given half cell reaction at pH = 5 ?_______
2H2O→O2+4H++4e− ; E°red=1.23V
( R=8.314Jmol−1K−1 ; Temp = 298 K; oxygen under std. atm. pressure of 1 bar)
[8 Jan 2020 Shift 1]
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