JEE Main 8 Jan 2020 Shift 1 Solved Paper

Since, Fe(OH)3 is positively charged sol, hence, anionic charge will flocculate
As per Hardy Schulze rules coagulation power of anion follows the order :
Fe(CN)63−>CrO42− >Cl−=Br−=NO3−
Higher the coagulation power lower will be its flocculation value
therefore order will be :
Fe(CN)63−<CrO42−< Cl−=Br−=NO3−