JEE Main 8 Jan 2020 Shift 1 Solved Paper

A particle is moving along the x-axis with its coordinate with the time 't' given be x(t)=10+8t−3t2. Another particle is moving the y-axis with its coordinate as a function of time given by y(t)=5−8t3. At t=1s, the speed of the second particle as measured in the frame of the first particle is given as √v. Then v (in m/s) is ____________.