The major product of the following reaction is : \C_6\H_5\CH_2-\C^{|↖{\CH_3}}_{|↙{\Br}}-\CH_2-\CH_3\stackrel{\C_2\H_5\ONa}{─\xrightarrow[C_2H_5OH]{} [Main 8 April 2017]

Correct Answer is : C6H5CH=C|CH3−CH2CH3

C_6H_5CH_2-C^{|↖{CH_3}}_{|↙{OC_2H_5}}-CH_2CH_3

C_6H_5CH=C_{|↙{CH_3}}-CH_2CH_3

C_6H_5CH_2-C_{|↙{CH_3}}-CHCH_3

C_6H_5CH_2-C_{|↙{CH_2CH_3}}=CH_2

JEE Main 8 April 2017 Paper Solved Paper

Section: Chemistry

Question : 59 of 90

Marks: +1, -0

The major product of the following reaction is :

C6H5CH2−

CH3

−CH2−CH3

C2H5‌ONa

────────▶

C2H5OH

[Main 8 April 2017]

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