The enthalpy change on freezing of 1 mol of water at 58°C to ice at −58°C is : (Given ∆_{\text{fus}}H=6kJmol^{-1} at 0°C, C_P(H_2O,l)=75.3Jmol ^{-1}K^{-1}, C_P(H_2O,s)=36.8Jmol^{-1}K^{-1}) [Main 8 April 2017]

Correct Answer is : 6.56kJmol−1

JEE Main 8 April 2017 Paper Solved Paper

Section: Chemistry

Question : 40 of 90

Marks: +1, -0

The enthalpy change on freezing of 1 mol of water at 58°C to ice at −58°C is :
(Given ∆fusH=6kJmol−1 at 0°C,
CP(H2O,l)=75.3Jmol−1K−1,
CP(H2O,s)=36.8Jmol−1K−1)

[Main 8 April 2017]

5.44kJmol−1
5.81kJmol−1
6.56kJmol−1
6.00kJmol−1

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