Let the value of \lambda for which the shortest distance between the lines \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4} and \frac{x-\lambda}{3}=\frac{y-4}{4}=\frac{z-5}{5} is {1}/{\sqrt{6}} be \lambda_1 and \lambda_2. Then the radius of the circle passing through the points (0,0), ( \lambda_1, \lambda_2 ) and ( \lambda_2, \lambda_1 ) is [8 Apr 2025 Shift 2]

JEE Main 8 Apr 2025 Shift 2 Paper

Section: Mathematics

Question : 8 of 75

Marks: +1, -0

Let the value of λ for which the shortest distance between the lines ‌

x−1

=‌

y−2

=‌

z−3

and ‌

x−λ

=‌

y−4

=‌

z−5

is ‌

√6

be λ1 and λ2. Then the radius of the circle passing through the points (0,0), ( λ1,λ2 ) and ( λ2,λ1 ) is

[8 Apr 2025 Shift 2]

Go to Question:

Prev Question

Next Question