{\HA}( {\aq}) ⇌ {\H}^{+}( {\aq})+ {\A}^{-}( {\aq}) The freezing point depression of a 0.1 m aqueous solution of a monobasic weak acid HA is 0.20^{\circ} {\C}. The dissociation constant for the acid is Given: {\K}_{ {\f}} ( {\H}_2 {\O}) =1.8 {\K} {\kg} {\mol}^{-1}, molality \equiv molarity [8 Apr 2025 Shift 2]

Correct Answer is : 1.38×10−3

JEE Main 8 Apr 2025 Shift 2 Paper

Section: Chemistry

Question : 53 of 75

Marks: +1, -0

HA(aq)⇌H+(aq)+A−(aq)
The freezing point depression of a 0.1 m aqueous solution of a monobasic weak acid HA is 0.20∘C. The dissociation constant for the acid is
Given: Kf(H2O)=1.8K‌kg‌mol−1, molality ≡ molarity

[8 Apr 2025 Shift 2]

1.1×10−2
1.38×10−3
1.90×10−3
1.89×10−1

Validate

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