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Question : 13 of 90
Marks:
+1,
-0
Solution:
‌(+)×−×(−2+3)=0‌(+)×+(−2+3)×=0‌⇒(+)−2+3)×=0‌⇒=λ(4−)‌⇒=λ(44−4+4−4+−)‌=λ(40−3+3)Now
‌(8−2+2+33−3+3)⋅λ(40−3+3)=1670‌⇒(41−5+5)⋅(40−3+3)×λ=1670)‌⇒(1640+15+15)λ=1670⇒λ=1‌‌ so ‌=40−3−3‌⇒||2=1600+9+9=1618
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