Let the area of the region enclosed by the curve {\y}=\min \{ \sin {\x}, \cos {\x}\} and the {\x}-axis between {\x}=-\pi to {\x}=\pi be {\A}. Then {\A}^2 is equal to ______. [8 Apr 2024 Shift 1]

JEE Main 8 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 29 of 90

Marks: +1, -0

Let the area of the region enclosed by the curve y=min{sin‌x,cos‌x} and the x-axis between x=−π to x=π be A. Then A2 is equal to ______.

[8 Apr 2024 Shift 1]

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