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JEE Main 8 Apr 2024 Shift 1 Solved Paper

Section: Mathematics
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Question : 27 of 90
 
Marks: +1, -0
Let α=
n
∑
r=0
(4r2+2r+1)nCr and β=(
n
∑
r=0
‌
‌nCr
r+1
)+‌
1
n+1
. If 140<‌
2α
β
<281, then the value of n is ______.
[8 Apr 2024 Shift 1]
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