The equations of two sides {\AB} and {\AC} of {\a} triangle A B C are 4 x+y=14 and 3 x-2 y=5, respectively. The point (2,-\frac{4}{3}) divides the third side {\BC} internally in the ratio 2: 1. The equation of the side {\BC} is : [8 Apr 2024 Shift 1]

JEE Main 8 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 13 of 90

Marks: +1, -0

The equations of two sides AB and AC of a triangle ABC are 4x+y=14 and 3x−2y=5, respectively. The point (2,−‌

) divides the third side BC internally in the ratio 2:1. The equation of the side BC is :

[8 Apr 2024 Shift 1]

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