JEE Main 8 Apr 2024 Shift 1 Solved Paper

Section: Mathematics
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Question : 1 of 90
 
Marks: +1, -0
The value of k∈ℕ for which the integral In=
1
∫
0
(1−xk)n‌dx
,n∈ℕ
, satisfies 147I20=148I21 is :
[8 Apr 2024 Shift 1]
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