Given that the slope of the tangent to a curve y=y(x) at any point (x, y) is {2 y}/{x^{2}} . If the curve passes through the centre of the circle x^2 + y^2 – 2x – 2y = 0, then its equation is : [8 Apr 2019 Shift 2]

Correct Answer is : xloge|y|=2(x−1)

JEE Main 8 Apr 2019 Paper 2 Solved Paper

Section: Mathematics

Question : 84 of 90

Marks: +1, -0

Given that the slope of the tangent to a curve y=y(x) at any point (x,y) is

. If the curve passes through the centre of the circle x2+y2–2x–2y=0, then its equation is :

[8 Apr 2019 Shift 2]

Go to Question:

Prev Question

Next Question