JEE Main 8 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

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Question : 61 of 90

Marks: +1, -0

If f(x)=loge(

1−x

1+x

),|x|<1, then f(

2x

1+x2

) is equal to

[8 Apr 2019 Shift 1]

2f(x)
(f(x))2
2f(x2)
−2f(x)

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