JEE Main 8 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 5 of 90

Marks: +1, -0

An alternating voltage v(t)=220‌sin‌100‌π‌t 220sin100 volt is applied to a purely resistive load of 50Ω. The time taken for the current to rise from half of the peak value to the peak value is:

[8 Apr 2019 Shift 1]

7.2 ms
5 ms
2.2 ms
3.3 ms

Validate

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