Given that {E^{ \Theta}}_{O_{2} \/ H_{2} O} =+1.23 V {E^{ \Theta}}_{S_{2} O_{8}^{2-} \/ S O_{4}^{2-}} =2.05 V {E^{ \Theta}}_{B r_{2} \/ B r} =+1.09 V {E^{ \Theta}}_{A u^{3+} \/ A u} =+1.4 V The strongest oxidizing agent is: [8 Apr 2019 Shift 1]

JEE Main 8 Apr 2019 Paper 1 Solved Paper

Section: Chemistry

Question : 44 of 90

Marks: +1, -0

Given that
EΘO2∕H2O=+1.23V
EΘS2O82−∕SO42−=2.05V
EΘBr2∕Br=+1.09V
EΘAu3+∕Au=+1.4V
The strongest oxidizing agent is:

[8 Apr 2019 Shift 1]

Go to Question:

Prev Question

Next Question