JEE Main 7 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

© examsiri.com

Question : 62 of 75

Marks: +1, -0

The value of a for which 4α‌

2

∫

−1

e−α|x|dx=5, is:

[7 Jan 2020 Shift 2]

loge
3
2
loge
4
3
loge2
loge√2

Go to Question:

Prev Question

Next Question