he number of ordered pairs (r, k) for which 6\times ^35C_r = (k^2 - 3)\times^36C_{r +1} where k is an integer, is : [7 Jan 2020 Shift 2]

JEE Main 7 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

Question : 57 of 75

Marks: +1, -0

he number of ordered pairs (r, k) for which 6×35Cr=(k2−3)×36Cr+1 where k is an integer, is :

[7 Jan 2020 Shift 2]

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