JEE Main 7 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 51 of 75

Marks: +1, -0

Let y=y(x) be a function of x satisfying y√1−x2=k−x√1−y2 where k is a constant and y(

1

2

)=−

1

4

. Then

dy

dx

at x=

1

2

, is equal to

[7 Jan 2020 Shift 2]

√5
2
−
√5
2
2
√5
−
√5
4

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