JEE Main 7 Jan 2020 Shift 1 Solved Paper

Section: Mathematics

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Question : 65 of 75

Marks: +1, -0

If f(a+b+1−x)=f(x), for all x, where a and b are fixed positive real numbers, then

1

a+b

‌

b

∫

a

x(f(x)+f(x+1))dx is equal to :

[7-Jan-2020 Shift 1]

b−1
∫
a−1
f(x)dx
b+1
∫
a+1
f(x+1)dx
b−1
∫
a−1
f(x+1)dx
b+1
∫
a+1
f(x)dx

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