A satellite of mass m is launched vertically upwards with an initial speed u from the surface of the earth. After it reaches height R (R = radius of the earth), it ejects a rocket of mass m /10 so that subsequently the satellite moves in a circular orbit. The kinetic energy of the rocket is (G is the gravitational constant; M is the mass of the earth): [7-Jan-2020 Shift 1]

Correct Answer is : 5m(u2−119200GMR)

m/20(u-\sqrt{\frac{2GM}{3R}})^2

{3m}/8(u+\sqrt{\frac{5GM}{6R}})^2

JEE Main 7 Jan 2020 Shift 1 Solved Paper

Section: Physics

Question : 16 of 75

Marks: +1, -0

A satellite of mass m is launched vertically upwards with an initial speed u from the surface of the earth. After it reaches height R (R = radius of the earth), it ejects a rocket of mass

so that subsequently the satellite moves in a circular orbit. The kinetic energy of the rocket is (G is the gravitational constant; M is the mass of the earth):

[7-Jan-2020 Shift 1]

m
20
(u−√
2GM
3R
)2
5m(u2−
119
200
GM
R
)
3m
8
(u+√
5GM
6R
)2
m
20
(u2+
113
200
GM
R
)

Validate

Go to Question:

Prev Question

Next Question