If the magnetic field in a plane electromagnetic wave is given by B^{\to}=3\times10^{-8} \sin(1.6\times10^3x+48\times10^10t)j ^{\^}, then what will be expression for electric field? [7-Jan-2020 Shift 1]

Correct Answer is : →E=9sin(1.6×103x+48×1010t)^kV∕m

E^{\to}=9\sin (1.6\times10^3x+48\times10^10t)k^{\^} V\/m

E^{\to}=3\times10^{-8}\sin (1.6\times10^3x+48\times10^10t)i^{\^} V\/m

E^{\to}=60\sin (1.6\times10^3x+48\times10^10t)k^{\^} V\/m

E^{\to}=3\times10^{-8}\sin (1.6\times10^3x+48\times10^10t)j^{\^} V\/m

JEE Main 7 Jan 2020 Shift 1 Solved Paper

Section: Physics

Question : 11 of 75

Marks: +1, -0

If the magnetic field in a plane electromagnetic wave is given by

→

=3×10−8 sin(1.6×103x+48×1010t)‌

, then what will be expression for electric field?

[7-Jan-2020 Shift 1]

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