JEE Main 7 Apr 2025 Shift 2 Paper
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Let y = y ( x ) ( x 2 + 1 ) y ′ − 2 x y = ( x 4 + 2 x 2 + 1 ) cos x y ( 0 ) = 1 ∫ − 3 3 y ( x ) dx
[7 Apr 2025 Shift 2]
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