JEE Main 7 Apr 2025 Shift 1 Paper

1 Faraday electricity was passed through Cu2+(1.5M,1L)∕Cu and 0.1 Faraday was passed through Ag+(0.2M,1L)∕Ag electrolytic cells. After this the two cells were connected as shown below to make an electrochemical cell. The emf of the cell thus formed at 298 K is ____ mV (nearest integer) ‌ Given : ‌ECu2+∕Cu∘=0.34V
EAg+∕Ag∘=0.8V
‌

2.303‌RT

F

=0.06V