JEE Main 6 Apr 2024 Shift 2 Solved Paper

Section: Mathematics

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Question : 6 of 90

Marks: +1, -0

lim

n⟶∞

‌

(12−1)(n−1)+(22−2)(n−2)+....+((n−1)2−(n−1))⋅1

(13+23+....+n3)−(12+22+.....+n2)

is equal to:

[6 Apr 2024 Shift 2]

‌
2
3
‌
1
3
‌
3
4
‌
1
2

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