JEE Main 6 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 8 of 90

Marks: +1, -0

For α,β∈R and a natural number n, let Ar=|

r

1

‌

n2

2

+α

2r

2

n2−β

3r−2

3

‌

n(3n−1)

2

|. Then 2A10−A8 is

[6 Apr 2024 Shift 1]

4α+2β
2α+4β
2n
0

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