JEE Main 6 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 12 of 90

Marks: +1, -0

Let the relations R1 and R2 on the set X={1,2,3,...,20} be given by R1={(x,y):2x−3y=2} and R2={(x,y):−5x+4y=0}. If M and N be the minimum number of elements required to be added in R1 and R2, respectively, in order to make the relations symmetric, then M+N equals

[6 Apr 2024 Shift 1]

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