JEE Main 5 Apr 2024 Shift 2 Solved Paper

Section: Mathematics

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Question : 10 of 90

Marks: +1, -0

If the constant term in the expansion of (‌

‌5√3

x

+‌

2x

‌3√5

)12,x≠0, is α×28×‌5√3, then 25α is equal to :

[5 Apr 2024 Shift 2]

639
724
693
742

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