JEE Main 5 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 22 of 90

Marks: +1, -0

If the constant term in the expansion of (1+2x−3x3)(‌

3

2

x2−‌

1

3x

)9 is p, then 108p is equal to

[5 Apr 2024 Shift 1]

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